# A bh 2 solve for h

Divide A-\frac{h}{2} by \frac{1}{2} by multiplying A-\frac{h}{2} by the reciprocal of \frac{1}{2}. A=\frac{1}{2}b+\frac{1}{2}h Divide each term of b+h by 2 to get \frac{1}{2}b+\frac{1}{2}h.

## How do you solve A=h/2(a+b) for h?

2 × A = 2 × h 2 (a +b) 2A = 2 × h 2 (a +b) 2A = h(a +b) Now, divide each side of the equation by a + b to solve for h while keeping the equation balanced: 2A a +b = h(a +b) a +b. 2A

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## A = (1/2)bh for h, solve for the specified value

Solve for h A=1/2(B+b)h. Step 1. Rewrite the equation as . Step 2. Multiply both sides of the equation by . Step 3. Simplify the left side. Tap for more steps Simplify . Tap for more steps

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## Solve for h in the formula for the area of a triangle A = bh/2

A= bh/2. Multiply each side by 2. 2A = bh/2 *2. 2A = bh. Divide by b. 2A/b = bh/b. 2A/b =h. Advertisement.

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## Given A=1/2(bh), solve for h.

Algebra. Solve for h a=bh. a = bh a = b h. Rewrite the equation as bh = a b h = a. bh = a b h = a. Divide each term in bh = a b h = a by b b and simplify. Tap for more steps h = a b h = a b.

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