sin(2x)=sinx

10. I've found two different ways to solve this trigonometric equation. sin ( 2 x) = sin ( x) ⇔ 2 sin ( x) cos ( x) = sin ( x) ⇔ 2 sin ( x) cos ( x) − sin ( x) = 0 ⇔ sin ( x) [ 2 cos ( x) − 1] = 0 ⇔ sin ( x) =

How to use a double angle identity to solve the equation sin2x

Solution: We know that double angle formula for sin is : \(Sin 2x = 2 Sin x Cos x\\\) Putting \(\ x = 45^{\circ} \\\) \(Sin (2 \times 45^{\circ}) = 2 \ Sin 45^{\circ} Cos 45^{\circ} \\\) Since \(\ Sin 45^{\circ} =\frac{1}{\sqrt{2}} \\\) \(Cos

Decide mathematic question

What is the value of x in the equation 3x + 5 = 17? The value of x in the equation 3x + 5 = 17 is 12.

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