F(g(h(x))) calculator
if h(x) = f [g(x)], then prove that ∇h(a) = ∑k=1n Dkf (b) ∇gk(a) You can't do h′(a) = ∇h(a)∘a because h is a scalar and a is a vector. Write h(x) as h(x) = f (g1(x),g2(x),,gn(x)) Then ∇h = (∂x1∂h,, ∂xn∂h) If h(x) = f (g(f (x))) is bijective, what do we know about f,g? Your proof is fine. It's also worth noting
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Math is a way of solving problems by using numbers and equations.
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I love solving math problems!
Solving equations becomes quick and simple. It teaches step by step, picture mode is amazing, split screen homework and this, and screenshot each question. I personally enjoy this app mainly because it is not like your typical calculator.
Walter Duprey
Plus it explains better than my actual math teacher hahahahaha, it also provide various options for asking your questions like scan the question or write the question with the mathematical keyboard, amazing math app, it makes solving problems a lot easier, great job, developers.
Michael Meads
Integration, differentiation) have to be included. Greatest calculator ever created. This is a lovely application for people who are not very good at maths and finds difficulty and some problems in solving hard as well as tricky questions of Maths.
Paul Warfield
