It turns out, and I'll prove this to you in the next video, it's a little bit of a hairy math problem, that the focal length of a hyperbola is equal to the square root of the sum of these two numbers, is equal to the sum of a squared plus b squared.

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foci\:\frac{y^2}{25}-\frac{x^2}{9}=1; foci\:\frac{(x+3)^2}{25}-\frac{(y-4)^2}{9}=1; foci\:4x^2-9y^2-48x-72y+108=0; foci\:x^2-y^2=1

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