amplitude A = 2; period 2 π /B = 2 π /4 = π /2; phase shift = −0.5 (or 0.5 to the right) vertical shift D = 3; In words: the 2 tells us it will be 2 times taller than usual, so Amplitude = 2; the usual period is 2 π, but in our case that is sped up
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How to find the period and amplitude of the function f (x) = 3 sin (6 (x − 0.5)) + 4 . Solution f (x) = 3 sin (6 (x − 0.5)) + 4 —————- eq no 1 As the given generic formula is: f (x) = A * sin (Bx – C) +
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We first need to identify the {eq}y {/eq}-value at the peak of the function
On a graph, multiplying the whole sine function by some number, A, looks like stretching or squashing the sine graph in the y -direction. The amplitude, A, is found by taking half the
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