Lim h approaches 0

For x = 0, it comes out to be 1, which is near to zero. Wait, put x = - 1, you will get the value as 0.1, this is close to 0. Again wait, put x = -2, you will get the value as 0.01, this is more close to zero.

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To evaluate the limit as h approaches 0, how do I rewrite the

Jan 13, 2008. #2. DINOCALC09 said: What is the. limit of [ tan (pi/6+h) - tan (pi/6) ] / h. as h approaches 0. First, tan ( x + y) = tan x + tan y 1 − tan x tan y. This means, tan ( π 6 + h)

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